How to Sort files and folders by size
Posted by admin on July 27th, 2007 
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You need to open terminal use the following command
ls -lS –block-size=1 | awk ‘ {print $5,$6,$7,$8}’ >size.txt; du -s –block-size=1 */ >>size.txt; sort -n size.txt
or
{ ls -lS –block-size=1 | awk ‘ {print $5,$6,$7,$8}’; du -s –block-size=1 */ ; } | sort -nr | less
August 2nd, 2007 at 3:05 pm
This is i think the first thing someone showed me my first day on the job as a unix admin may years ago.
$ du -s * |sort -n
with gnu du you can add -m to get the output in megs. ( du -sh * is nice too but won’t sort)
$ du -sm * |sort -n
Many Many hours of a Unix admins life is spent doing du -s * |sort -n then cd to the last directory and repeat ….
If your looking for what filled up your filesystem that wasn’t full an hour ago you can also whip together a big find command to find all files over say 100 megs that where modified in the last hour.
Eli Criffield
August 5th, 2007 at 4:47 am
You can do this to:
for i in `du -s * |sort -n |cut -f2`; do du -h $i; done
August 13th, 2007 at 12:43 am
Also you can try this:
ls -Slh|cut -c32-36,52-