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You need to open terminal use the following command
ls -lS --block-size=1 | awk ‘ {print $5,$6,$7,$8}' >size.txt; du -s --block-size=1 */ >>size.txt; sort -n size.txt
or
{ ls -lS --block-size=1 | awk ‘ {print $5,$6,$7,$8}'; du -s --block-size=1 */ ; } | sort -nr | less
This is i think the first thing someone showed me my first day on the job as a unix admin may years ago.
$ du -s * |sort -n
with gnu du you can add -m to get the output in megs. ( du -sh * is nice too but won’t sort)
$ du -sm * |sort -n
Many Many hours of a Unix admins life is spent doing du -s * |sort -n then cd to the last directory and repeat ….
If your looking for what filled up your filesystem that wasn’t full an hour ago you can also whip together a big find command to find all files over say 100 megs that where modified in the last hour.
Eli Criffield
You can do this to:
for i in `du -s * |sort -n |cut -f2`; do du -h $i; done
Also you can try this:
ls -Slh|cut -c32-36,52-
Along the lines of Eli Crffield’s post (but showing everything underneath, instead of just the pwd) how about:
du -ab | sort -n
BTW, I forgot… for those of you who prefer gui interaction, there’s always something like “kfind” and “gnome-find” too. Ah… so many ways to slice the onion!
du -h | sort -n #works fine for me
ls -lSh works for me.
ls -lrSh
Same deal as Travis but larger files sorted to the bottom of the list.
To get a sorted human-readable output of the file size and name you can use:
ls -lSh *.ogg | awk ‘{print $6 “\t” $9}’
Since the previous solution works only on files (ls reports the default block size for directories), here’s a second (slower) solution that works on mixed (directories and files) lists:
du -s ~/* | sort -rn | awk ‘{print $2}’ | xargs du -sh